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(MECH3010)[2013](s)midterm~=vgzo_ee^_49372.pdf
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FL FL
St Al
= (2)
EA EA
St Al
(1) and (2) .
Ed
x = Al = 0.412m (3)
E + E
Al St
(b)
.F + F = P
.St Al
. (4)
.Fx = F (d . x)
. St Al
FL FL
St Al
+TL =+TL (5)
St Al
EA EA
St Al
(4) and (5) .
x = 0.3088m
(c) From (3) we can see x is independent of P, so the equilibrium will be remained.