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(ELEC102)test1_pastg.pdf
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(16)

1

20.

20.

Va+ 20V

80V

0V

(10)

20.

20V

3.5A/3

110V/3

170V/3

0V

20.

5.5A/3

9.5A/3

Va

(160)



(17)

+
-

1F

V(t)

t (sec)

2




Text Box: For the given I(t), find and plot V(t). Find also the maximum energy stored in X. Given X = 1mF, V(0) = 0V. (17)




Text Box: (5)
Text Box: (5)
Text Box: (2)


Text Box: (5)


3

(14)

2k.

v(<0) =18V

(5)

9m

(3)

2k.

9m

(4)

(2)


Text Box: The switch has been closed for a long time. At t = 0 second, the switch is opened. Find v(0) , v(.V), i(0), and


Text Box: t < 0


Text Box: t .d 0






(10)

4

18V

6mA

18V

6mA

45V


Text Box: . Use loop current method to find Io . (10)









Text Box: 3m/4

Text Box: IX

(18)

(6)

5

(5)

(2)

2k.

(3)

(2)



Text Box: For the audio amplifier, when R = 0.., Io = 2.5mA.When R = 8k.., Vo is 4V.Find the Thevenin equivalent of the audio



Text Box: when R = 0.., Io = 2.5mA, Hence Isc of audio oscillator = 2.5mA.




Text Box: Use Norton equivalent

6

(4)

(16)



Text Box: If D = 1mH, find v(t). Find the power consumed or delivered by E . Is E a passive element? Find also the maxim
Text Box: P = V*i(t) = (-3V-3V)(-1A) = 6W consumed
Text Box: passive element


Text Box: (4)

Text Box: If D = 1mH

7

(23)

1.

2.

1.

6A

0V

1.

4A

2V

14V

4V

1.

a

2.

2A

a



Text Box: (a) If load = 2.., use superposition method to find Io. (b) Find the Norton resistance at terminals ab. (23)



Text Box: (8)



Text Box: (8)

Text Box: (2)





8

(25)

(3)

(3)

(3)

(6)

(6)



Text Box: A digital multi-meter (DMM) with a bandwidth of 20kHz is used to measure a 8 sin ( 2 . f * t) V signal. (a) If f
Text Box: (d)
Text Box: (b)
Text Box: (c)

Text Box: 0V

Text Box: R of A is larger since P = V2/R. In series, P = i2R, hence A is brighter
Text Box: (e)

(21)

9

4./9

16V/18

4.











Text Box: (10)
Text Box: (7)
Text Box: (4)