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(ELEC101)T02Example.pdf
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Example 1: (From D2.10 Introduction to Electrical Engineering by Irwin)
Find the equivalent resistance at the terminal A-B in Fig 1.










Answers to Example 1:














Combining the 2 and 1 resistors on the right and the two 2 resistors in the middle, we get a simplified circuit as shown on right

Further reduce the parallel resistors together we get the reduced circuit

So, we get RAB = 7

Fig. 1







Example 2: (From P2-16, Circuits, Devices and Systems by Smith and Dorf)
Find current I in the ladder network of Fig 2 by network reduction. Reduce series and parallel combinations to a single equivalent resistance, find the battery current, then use current division to find I.








Answers to Example 2:

Fig. 2

6 and 4 resistors are in series

Example 3: (From AP2-1, Circuits, Devices and Systems by Smith and Dorf)
Given the circuit of Fig. 3, consider various methods to calculate the current in the 5 resistance. Use the method that appears to require the least algebra.










Answers to Example 3:

Actually, you can define any loop current you want. However, in this example, we should carefully select the loop.










Apply KVL for loop

.. (1)
Apply KVL for loop

.. (2)
i3 = 3A

From (1) From (2)

Solving, we get = .4A, and = 6A




is the current flowing through the 5 resistor.